Question

A container is filled with a gas at 10 atm with molar volume 1 liter/mole, if B = – 0.053 liter/mole, C = 0.0026 liter^2/mole^2, what is the temperature of gas? (Use virial equation, neglect higher terms)

(a) 128.2 K

(b) 156.9 K

(c) 198.5 K

(d) 243.6 K

The question was asked in final exam.

This is a very interesting question from Equations of State in chapter Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer 1

Right choice is (a) 128.2 K

To explain: PV = RT(1 + B/V + C/V^2), => T = 10*1/[0.0821*(1 – 0.053/1 + 0.0026/1^2)] = 128.2 K.