Arrhenius equation to determine the activation energy.
(a) ln\((\frac{k1}{k2}) = \frac{E}{R} (\frac{1}{T2}-\frac{1}{T1}) \)
(b) ln\((\frac{k1}{k2}) = \frac{E}{R} (\frac{1}{T2}+\frac{1}{T1}) \)
(c) ln\((\frac{k1}{k2}) = -\frac{E}{R} (\frac{1}{T2}-\frac{1}{T1}) \)
(d) ln\((\frac{k1}{k2}) = \frac{E}{R} (\frac{T1}{T2}) \)
I had been asked this question during an internship interview.
My question is based upon Rate Laws and Stoichiometry Definitions in section Rate Laws and Stoichiometry of Chemical Reaction Engineering