Question

For the reaction -rA = \(\frac{1670[A][Po]}{6+CA} \frac{kmol}{ml.hr}\) write the units for constants 6 and 1670.

(a) kmol/ml and 1/hr

(b) 1/hr and 1/hr

(c) kmol and kmol

(d) data insufficient

This question was addressed to me at a job interview.

My question is from Rate Laws and Stoichiometry Definitions in section Rate Laws and Stoichiometry of Chemical Reaction Engineering

Answer 1

The correct option is (a) kmol/ml and 1/hr

The explanation: To get the final units

-rA = \(\frac{1670[\frac{kmol}{ml}][\frac{kmol}{ml}]}{6+\frac{kmol}{ml}} \)

The units of constants have to be 1/hr for 1670 and kmol/ml for 6.