Correct answer is (c) \(H_2+2OH^-\rightarrow 2H_2 O+ 2e^-\)
Explanation: \(H_2+\frac{1}{2} O_2 \rightarrow H_2 O\) is an overall reaction whereas \(H_2 O \rightarrow H_2+ O_2\) is an unbalanced reaction. \(O_2+H_2 O+ 2e^-\rightarrow HO_2^-+ OH^-\) is a reduction reaction which takes place at cathode, and \(H_2+2OH^-\rightarrow 2H_2 O+ 2e^-\) is the anodic reaction (oxidation reaction).