Correct option is (c) 2CH2=CHCN+2H2 O+2e^–→NC – (CH2)4 – CN+2OH^–
To explain I would say: Reaction H2O →2H^++\(\frac{1}{2}\) O2+ 2e^– takes place at anode since it is an oxidation reaction. In the reaction 2CH2=CHCN+2H2O + 2e^– → NC-(CH2)4-CN, charge is unbalanced. Reaction 2CH2=CHCN+2H2O+2e^–→NC-(CH2)4-CN+2OH^– takes place at cathode.