Right answer is (a) \(\frac{1}{2}\) O2+ CO2+ 2e^– →CO3^-2
Best explanation: \(\frac{1}{2}\) O2+ CO2+ 2e^– →CO3^-2 being reduction reaction takes place at cathode. C+2CO3^-2 →3CO2+ 4e^– Is an anodic reaction for CH4, CO+CO3^-2 → 2CO2+ 2e^– is an anodic reaction for CO and H2+ CO3^-2 → H2 O+CO2+ 2e^– is an anodic reaction for H2.