The correct choice is (b) Straight line
To elaborate: Let A (2, -1) and B (3, 2) be the given points and (x, y) be the co-ordinates of a point P on the required locus. Then,
PA^2 = (x – 2)^2 + (y + 1)^2 and PB^2 = (x – 3)^2 + (y – 2)^2
By problem, PA = PB or, PA^2 = PB^2
or, (x – 2)^2 + (y + 1)^2 = (x – 3)^2 + (y – 2)^2 or, x^2 – 4x + 4 + y^2 + 2y + 1 = x^2 – 6x + 9 + y^2 – 4y + 4
or, 2x + 6y = 8 or, x + 3y = 4 ……… (1)
Clearly, equation (1) is a first degree equation in x and y; hence, the locus of P is a straight line whose equation is x + 3y = 4.