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The generated e.m.f from 50-pole armature having 400 conductors driven at 20 rev/sec having flux per pole as 30 mWb, with lap winding is ___________

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The generated e.m.f from 50-pole armature having 400 conductors driven at 20 rev/sec having flux per pole as 30 mWb, with lap winding is ___________

(a) 230 V

(b) 140 V

(c) 240 V

(d) 250 V

The question was posed to me in semester exam.

This intriguing question originated from Dynamics in portion Dynamics of Electrical Drives of Electric Drives

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Best answer
Right choice is (c) 240 V

Best explanation: The generated can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux per pole, Z represents the total number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. In lap winding number of parallel paths are equal to the number of poles. Eb = .03×50×400×1200÷60×50= 240 V.

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