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The generated e.m.f from 42-pole armature having 74 turns driven at 64 rev/sec having flux per pole as 21 mWb, with wave winding is ___________

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The generated e.m.f from 42-pole armature having 74 turns driven at 64 rev/sec having flux per pole as 21 mWb, with wave winding is ___________

(a) 4177.171 V

(b) 4177.152 V

(c) 4100.189 V

(d) 4190.454 V

This question was addressed to me in exam.

The query is from DC Motors in division Characteristics of DC & AC Motors of Electric Drives

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The correct answer is (b) 4177.152 V

The explanation is: The generated e.m.f can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux per pole, Z represents the total number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. One turn is equal to two conductors. In wave winding the number of parallel paths is equal to two. Eb=.021×42×74×2×3840÷60×2=4177.152 V.

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