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The generated e.m.f from 22-pole armature having 75 turns driven at 78 rpm having flux per pole as 400 mWb, with lap winding is ___________

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The generated e.m.f from 22-pole armature having 75 turns driven at 78 rpm having flux per pole as 400 mWb, with lap winding is ___________

(a) 76 V

(b) 77 V

(c) 78 V

(d) 79 V

I had been asked this question in homework.

The query is from Methods to Reduce the Energy Loss During Starting topic in chapter Starting of Electric Drives

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Correct option is (c) 78 V

Best explanation: The generated e.m.f can be calculated using the formula Eb = Φ×Z×N×P÷60×A, Φ represent flux per pole, Z represents the total number of conductors, P represents the number of poles, A represents the number of parallel paths, N represents speed in rpm. One turn is equal to two conductors. In lap winding, the number of parallel paths is equal to a number of poles. Eb = .4×22×75×2×78÷60×22 = 78 V.

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