Question

A hydel plant is supplied from a reservoir of 5 X 10^6 m^3 capacity at a head of 75m. Determine the number of electrical units produced (KWh) during the year if the load factor is 0.6 and overall efficiency of generation is 72%?

(a) 441.45MWh

(b) 300.22MWh

(c) 235MWh

(d) 182MWh

I got this question in quiz.

My question comes from Hydrographs in portion Hydro Electric Power Plant of Energy Engineering

Answer 1

The correct answer is (a) 441.45MWh

The best I can explain: The power capacity of plant in KW is given as

  P = mgH/1000 X n{overall}

     = (5 X 106 X 1000 X 9.81 X 75 X 0.72) / (365 X 24 X 3600 X 1000)

    = 83.99Kw

  Energy produced in kWh = P X Load factor X (365 X 24)

       = 83.99 X 0.6 X 365 X 24

       = 4441451.44kwh

       = 441.45 Mwh.