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Mean diameter of coil is 100 mm and inner diameter is 95 mm, spring index is __________

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Mean diameter of coil is 100 mm and inner diameter is 95 mm, spring index is __________

(a) 10

(b) 5

(c) 12

(d) 15

This question was addressed to me during a job interview.

My question is taken from Construction of Helical Springs in portion Curves used in Engineering Practice of Engineering Drawing

1 Answer

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Right answer is (a) 10

The best explanation: Spring index is the ratio of mean diameter of coil to diameter of wire. Outer diameter = inner diameter + 2 x diameter of wire. So here diameter of wire is 10 mm. Spring index = 100mm/10mm = 10.

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