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Inner diameter of the coil is 70 mm and diameter of wire is 8 mm, spring index is ________

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Inner diameter of the coil is 70 mm and diameter of wire is 8 mm, spring index is ________

(a) 9.25

(b) 8.75

(c) 9.75

(d) 7.8

This question was addressed to me in an international level competition.

My doubt is from Construction of Helical Springs topic in portion Curves used in Engineering Practice of Engineering Drawing

1 Answer

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Right option is (c) 9.75

The explanation: Outer diameter = inner diameter + 2 x diameter of wire, outer diameter = 70 +2 x 8 = 86 mm. Spring index = mean diameter of coil / diameter of wire. Spring index = ((86+70)/2)/8 = 9.75.

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