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A Spring is made of wire whose cross-section is a square of 15 mm side. Inner diameter of spring is 60 mm then outer diameter will be _________

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A Spring is made of wire whose cross-section is a square of 15 mm side. Inner diameter of spring is 60 mm then outer diameter will be _________

(a) 45

(b) 75

(c) 90

(d) 80

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My question is based upon Construction of Helical Springs topic in division Curves used in Engineering Practice of Engineering Drawing

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The correct answer is (c) 90

Easiest explanation: Outer diameter is equal to the sum of the inner diameter and 2 times the diameter of a wire. Here the cross section of wire is square so diameter can be considered as 15 mm. outer diameter = 60 +2 x 15 = 90 mm.

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