Right answer is (d) 22
Easy explanation: Simplifying the expression we have
\(lt_{(x,y,z,w)\rightarrow(3,1,1,11)}\frac{(x^2+y+z)^2-(w)^2}{x^2+y+z-w}\)
\(lt_{(x,y,z,w)\rightarrow(3,1,1,11)}\frac{(x^2+y+z+w).(x^2+y+z-w)}{x^2+y+z-w}\)
\(lt_{(x,y,z,w)\rightarrow(3,1,1,11)}(x^2+y+z+w)\)=(3^2+1+1+11)
=9+1+1+11=22