The correct choice is (d) 8
The explanation: Simplifying the expression yields
\(lt_{(x,y,z)\rightarrow(0,0,0)}\frac{(x+y)^2-z^2}{(x+y)-z}\)
\(lt_{(x,y,z)\rightarrow(0,0,0)}\frac{(x+y+z).(x+y-z)}{(x+y-z)}\)
\(lt_{(x,y,z)\rightarrow(0,0,0)}(x+y+z)=2+2+4\)
=8