Correct choice is (d) ^-16⁄105
Best explanation: Rewriting the function as
\(\int_{0}^{\frac{\pi}{2}} cos^3(x).cos(2x)dx=2\int_{0}^{\frac{\pi}{2}} cos^7(x)dx-\int_{0}^{\frac{\pi}{2}} cos^5(x)dx\)
We now use the formula
\(\int_0^{\frac{\pi}{2}} cos^n(x)dx=\frac{(n-1).(n-3)…2}{n.(n-2)…\times 1}\)
\(=2.\frac{6.4.2}{7.5.3.1}-\frac{4.2}{5.3.1}=\frac{4.2.-2}{5.3.1.7}\)
=\( \frac{16}{105}\)