Right option is (b) 1
Explanation: Using the formula
\(\int_{0}^{\frac{\pi}{2}} x^a.sin(x)dx=\left ((\frac{\pi}{2})^{a-1}-(a-1)\int x^{a-2}sin(x)\right)\)
We have
\(\int_{0}^{\frac{\pi}{2}} x^4.sin(x)dx=4.\left ((\frac{\pi}{2})^{3}-3\int_0^{\frac{\pi}{2}} x^{2}sin(x)dx\right)\)
4((π/2)^3-3π+1)