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What is the degree of the differential equation, 4x^3-6x^2 y^3+2y=0?

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What is the degree of the differential equation, 4x^3-6x^2 y^3+2y=0?

(a) 3

(b) 5

(c) 1

(d) 8

I have been asked this question in an online interview.

I need to ask this question from Basic Definitions in chapter Ordinary Differential Equations – First Order & First Degree of Engineering Mathematics

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Best answer
Correct option is (b) 5

The best explanation: The degree of an equation that has not more than one variable in each term is the exponent of the highest power to which that variable is raised in the equation. But when more than one variable appears in a term, it is necessary to add the exponents of the variables within a term to get the degree of the equation. Hence, the degree of the equation, 4x^3-6x^2 y^3+2y=0, is 2+3 = 5.

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