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The volume of an auditorium is 12,000m^3. Its reverberation time is 1.5 seconds. If the average absorption coefficient of interior surfaces is 0.4 Sabine/m^2. Find the area of interior surfaces.

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The volume of an auditorium is 12,000m^3. Its reverberation time is 1.5 seconds. If the average absorption coefficient of interior surfaces is 0.4 Sabine/m^2. Find the area of interior surfaces.

(a) 20,000m^2

(b) 3340m^2

(c) 4500m^2

(d) 450m^2

The question was posed to me during a job interview.

My question is from Reverberation topic in portion Waves of Engineering Physics I

1 Answer

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Correct answer is (b) 3340m^2

The best explanation: Reverberation time = 0.167V/aS

Total surface area S=3340m^2.

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