The correct choice is (a) 0, 4/π
Explanation: Signal is odd and ω = \(\frac{2π}{t}\) = π
Here, c0 = a0 = 0
So, cn = bn = \(2\int_0^t f(t).sinωt \,dt\)
∴ c1 = b1 = \(2\int_0^t sinωt \,dt\)
= \(\frac{2}{ω}[cosωt]_0^t\)
= \(-\frac{2}{π}\)[-1-1] = 4/π
So, the first two components are 0, 4/π.