Question

The rms value of a rectangular wave of period T, having value +V for a duration, T1(<T) and –V for the duration, T-T1 = T2 is __________

(a) V

(b) \(\sqrt{V}\)

(c) \(\frac{\sqrt{V}}{2}\)

(d) 0

This question was posed to me in examination.

I want to ask this question from Fourier Analysis topic in chapter Fourier Analysis on Complex Spaces of Signals and Systems

Answer 1

Right choice is (a) V

To explain I would say: \(\sqrt{V^2}\)n: Mean square value = \(\frac{1}{T}[∫_0^{T_1} V^2 \,dt + ∫_1^T V^2 \,dt] \)

Where, T1 + T2 = T

= \(\frac{1}{T}\)[V^2 T1 + V^2 T – V^2 T1] = V^2

∴ RMS = V.