The correct option is (d) Non-causal, linear and time variant
Explanation: Let y (t) = x (t^2). We can infer that y (t) depends on x (t^2) i.e. on future values of input if t>1. Hence, the system is non-casual.
Again, α x1(t) → y1 (t) = α x1(t^2) and β x2(t) –> y2 (t) = β x2(t^2)
Therefore α x1(t) + β x2(t) –> y (t) = α x1(t^2) + β x2(t^2) = y1 (t) + y2 (t), which implies that the system is linear.
Again, x (t) = u (t) – u (t-z) –> y (t) and X1(t) = x (t – 1) –> y1 (t).
So, we get, y1 (t) ≠ y (t –1), which implies that the system is time varying.