Question

Find the Norton’s current in the circuit shown below.

(a) 40∠30⁰

(b) 40∠-30⁰

(c) 30∠30⁰

(d) 30∠-30⁰

This question was posed to me in final exam.

This is a very interesting question from Norton’s Theorem in division Steady State AC Analysis of Network Theory

Answer 1

Correct choice is (c) 30∠30⁰

Best explanation: The Norton’s current is equal to the current passing through the short circuit between the points a and b. So the current passing through the short circuited terminals ‘a’ and ‘b’ is I = 30∠30⁰A.