The correct answer is (b) 8.57 Ω
Easiest explanation: For a parallel RLC circuit, \(\frac{d^2 V}{dt^2} + \frac{1}{RC} \frac{dV}{dt} + \frac{V}{LC}\) = 0
Solving the 2nd order differential equation, we get, 2rωn = \(\frac{1}{RC}\) and ωn = \(\frac{1}{\sqrt{LC}}\)
As, r=1,
∴ R = \(\frac{1}{2} \sqrt{\frac{L}{C}} \)
= \(\frac{1}{2} \sqrt{\frac{7}{\frac{1}{42}}} = \frac{1}{2}\) × 17.15 = 8.57 Ω.