Question

In the circuit given below, the equivalent capacitance is ____________

(a) 1.625 F

(b) 1.583 F

(c) 0.583 F

(d) 0.615 F

The question was asked by my college professor while I was bunking the class.

The above asked question is from Problems Involving Dot Conventions in division Resonance & Magnetically Coupled Circuit of Network Theory

Answer 1

The correct choice is (d) 0.615 F

Best explanation: CCB = \(\left(\frac{C_2 C_3}{C_2+ C_3}\right)\) + C5 = 1.5 F

Now, CAB =\(\left(\frac{C_1 C_{CB}}{C_1+ C_{CB}}\right)\) + C6 = 1.6 F

CXY = \(\frac{C_{AB}  × C_4}{C_{AB} + C_4}\) = 0.615 F.