Question

In the circuit given below, the equivalent capacitance is ______________

(a) 3.5 μF

(b) 1.2 μF

(c) 2.4 μF

(d) 4.05 μF

I got this question by my college director while I was bunking the class.

This interesting question is from Problems Involving Dot Conventions in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Answer 1

Correct choice is (d) 4.05 μF

To elaborate: The 2.5 μF capacitor is in parallel with 1 μF capacitor and this combination is in series with 1.5 μF.

Hence, C1 = \(\frac{1.5(2.5+1)}{1.5+2.5+1}\)

= \(\frac{5.25}{5}\) = 1.05

Now, C1 is in parallel with the 3 μF capacitor.

∴ CEQ = 1.05 + 3 = 4.05 μF.