Question

What is the steady state value of F (t), if it is known that F(s) = \(\frac{1}{(s-1)(s+2)}\)?

(a) 1

(b) –\(\frac{1}{2}\)

(c) \(\frac{1}{2}\)

(d) Cannot be determined

This question was addressed to me in exam.

The doubt is from Problems on Initial and Final Value Theorem in chapter Application of the Laplace Transform in Circuit Analysis of Network Theory

Answer 1

The correct answer is (d) Cannot be determined

For explanation I would say: The steady state value of this Laplace transform is cannot be determined since; F(s) has a pole s = 1. Hence the answer is that it cannot be determined.