Question

What is the steady state value of F (t), if it is known that F(s) = \(\frac{10}{(s+1)(s^2+1)}\)?

(a) -5

(b) 5

(c) 10

(d) Cannot be determined

I have been asked this question in homework.

This is a very interesting question from Problems on Initial and Final Value Theorem topic in division Application of the Laplace Transform in Circuit Analysis of Network Theory

Answer 1

Right answer is (d) Cannot be determined

Explanation: The steady state value of this Laplace transform is cannot be determined since; F(s) is having two poles on the imaginary axis (j and –j). Hence the answer is that it cannot be determined.