Question

For the circuit given below, the value of the Inverse hybrid parameter g11 is ___________

(a) 0.067 Ω

(b) 0.025 Ω

(c) 0.3 Ω

(d) 0.25 Ω

The question was asked during an online exam.

Origin of the question is Inverse Hybrid (g) Parameter in portion Two-Port Networks of Network Theory

Answer 1

Right answer is (a) 0.067 Ω

The explanation is: Inverse Hybrid parameter g11 is given by, g11 = \(\frac{I_1}{V_1}\), when I2 = 0.

Therefore short circuiting the terminal Y-Y’, we get,

 V1 = I1 ((10||10) + 10)

= I1 \(\left(\left(\frac{10×10}{10+10}\right)+10\right)\)

= 15I1

∴ \(\frac{I_1}{V_1} = \frac{1}{15}\) = 0.067 Ω

Hence g11 = 15 Ω.