Correct answer is (b) 0.5 Ω
The best explanation: Inverse Hybrid parameter g21 is given by, g21 = \(\frac{V_2}{V_1}\), when I2 = 0.
Therefore short circuiting the terminal Y-Y’, and applying Kirchhoff’s law, we get,
V1 = I1 (10 + 10)
V2 = I1 10
∴ \(\frac{V_2}{V_1} = \frac{I_1 10}{I_1 20}\) = 0.5
Hence g21 = 0.5 Ω.