Question

For the circuit given below, the value of the Inverse hybrid parameter g22 is ___________

(a) 7.5 Ω

(b) 5 Ω

(c) 6.25 Ω

(d) 3 Ω

The question was posed to me in a job interview.

Question is taken from Inverse Hybrid (g) Parameter topic in division Two-Port Networks of Network Theory

Answer 1

The correct answer is (a) 7.5 Ω

For explanation: Inverse Hybrid parameter g22 is given by, g22 = \(\frac{V_2}{I_2}\), when V1 = 0.

Therefore short circuiting the terminal X-X’ we get,

-5 I2 – 5 I1 + V2 = 0

-5 I1 – 5(I1 – I2) = 0

Or, 2I1 = I2

Putting the above equation in the first equation, we get,

-7.5 I2 = -V2

Or, \(\frac{V_2}{I_2}\)  = 7.5

Hence g22 = 7.5 Ω.