The correct option is (d) [Z1; Z1; Z1; Z1 + Z2]
To explain I would say: z11 = \(\frac{V_1}{I_1}\), when I2 = 0
z22 = \(\frac{V_2}{I_2}\), when I1 = 0
z12 = \(\frac{V_1}{I_2}\), when I1 = 0
z21 = \(\frac{V_2}{I_1}\), when I2 = 0
Now, in the given circuit putting I1 = 0, we get,
z12 = Z1 and z22 = Z1 + Z2
And putting I2 = 0, we get,
z21 = Z1 and z11 = Z1.