Question

The maximum kinetic energy of a photoelectron is 3 eV. What is the stopping potential?

(a) 0 V

(b) 3 V

(c) 9 V

(d) 12 V

The question was asked in unit test.

My doubt stems from Einstein’s Photoelectric Equation : Energy Quantum of Radiation topic in section Dual Nature of Radiation and Matter of Physics – Class 12

Answer 1

Right answer is (b) 3 V

For explanation I would say: Stopping potential is given as:

V0 = \(\frac {K_{max}}{e}\)

V0 = \(\frac {3eV}{e}\)

V0 = 3 V

Therefore, the stopping potential is 3 V.