Question

What will be the value of k, if one zero of x^2+(k-3)x-16=0 is additive inverse of other?

(a) 4

(b) -4

(c) -3

(d) 3

This question was addressed to me in unit test.

The above asked question is from Zeros and Coefficients of Polynomial topic in division Polynomials of Mathematics – Class 10

Answer 1

The correct choice is (d) 3

The explanation is: Since, one zero of the polynomial is the additive inverse of the other.

Hence, the sum of roots will be zero.

The polynomial is x^2+(k-3)x-16=0

Sum of zeros or α+β=\(\frac {-coefficient \, of \, x}{coefficient \, of \, x^2} = \frac {k-3}{1}\)=0

k-3=0

k=3