Right option is (b) 5
Easiest explanation: One zero of the quadratic polynomial is 5. ∴ the factor of the polynomial is (x-5)
Let us assume the other zero to be b. ∴ the other factor of the polynomial is (x-b)
Multiplying the factors, we have (x-5)(x-b)
x^2-5x-bx+5b
x^2-(5+b)x+5b
The sum of zeros is 10.
∴ \(\frac {-coefficient \, of \, x}{coefficient \, of \, x^2}\)=10
\(\frac {-(-5-b)}{1}\)=10
5+b=10
b=5
The equation becomes x^2-10x+25.
Therefore, the other zero is 5.