Right answer is (d) -1
The best I can explain: The given polynomial is x^3 – 9x^2 – x + 9.
The two zeros of the polynomial are 1 and 9.
We know that, the sum of zeros of the polynomial or α + β + γ = \(\frac {-coefficient \, of \, x^2}{coefficient \, of \, x^3} = \frac {9}{1}\)
1 + 9 + γ = 9
γ = 9 – 10 = -1