Right option is (b) x^4-90x^2+729
To explain I would say: The zeros of the polynomial are 3, -3, 9 and -9.
Then, (x-3), (x+3), (x-9) and (x+9) are the factors of the polynomial.
Multiplying the factors, we have
(x-3) (x+3) (x-9) (x+9)
(x^2-9) (x^2-81) (By identity (x-a)(x+a)=x^2-a^2)
(x^4-9x^2-81x^2+729)
x^4-90x^2+729