Right answer is (a) 6.40 cm
To elaborate: ABCD is a rhombus. The length of diagonal is 10 cm and the length of other diagonal is 8 cm.
Since, diagonals of a rhombus bisect each other. Therefore, AE = 4cm and DE = 5 cm
Now, in ∆AED
AD^2 = AE^2 + DE^2
AD^2 = 4^2 + 5 ^2 (Since, AD is the altitude of the triangle it will bisect BC)
AD^2 = 16 + 25
AD^2 = 41
AD = √41 cm = 6.40 cm