Question

Differentiate 8e^-x+2e^x w.r.t x.

(a) 2e^-x+8e^x

(b) 2e^x+8e^-x

(c) 2e^-x-8e^x

(d) 2e^x-8e^-x

I had been asked this question in homework.

My question is taken from Exponential and Logarithmic Functions topic in section Continuity and Differentiability of Mathematics – Class 12

Answer 1

Right choice is (d) 2e^x-8e^-x

To explain: To solve:y=(8e^-x+2e^x)

Differentiating w.r.t x we get,

\(\frac{dy}{dx}\)=8(-e^-x+2e^x)

∴\(\frac{dy}{dx}\)=2e^x-8e^-x.