The correct answer is (c) 5
The best explanation: Let \(I=\int_0^{\frac{π}{2}} \,5 \,sinx \,dx\)
F(x)=\(\int5 \,sinx \,dx=-5 \,cosx\)
Applying the limits by using the fundamental theorem of calculus, we get
I=F(\(\frac{π}{2}\))-F(0)
∴\(\int_0^{\frac{π}{2}} \,5 \,sinx \,dx=-5[cos\frac{π}{2}-cos0]\)
=-5[0-1]=5