Question

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white and the first ball drawn is green? The balls are replaced in the bag.

(a) \(\frac {1}{9}\)

(b) \(\frac {2}{9}\)

(c) \(\frac {8}{81}\)

(d) \(\frac {2}{81}\)

I had been asked this question in an online quiz.

My question is based upon Probability topic in division Probability of Mathematics – Class 12

Answer 1

Right choice is (c) \(\frac {8}{81}\)

For explanation I would say: Total number of balls = 9

The probability of the first ball to be white = \(\frac {2}{9}\)

The probability of drawing green ball for the second time with replacement = \(\frac {4}{9}\)

Total probability = \(\frac {2}{9} \times \frac {4}{9} = \frac {8}{81}\)