Question

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be green if the first ball drawn is red? The balls are replaced in the bag.

(a) \(\frac {3}{9}\)

(b) \(\frac {4}{27}\)

(c) \(\frac {4}{3}\)

(d) \(\frac {4}{17}\)

The question was asked in semester exam.

The doubt is from Probability in chapter Probability of Mathematics – Class 12

Answer 1

Right option is (b) \(\frac {4}{27}\)

The best explanation: Total number of balls = 9

The probability of the first ball to be red = \(\frac {3}{9}\)

The probability of the second ball to be green with replacement = \(\frac {4}{9}\)

Total probability = \(\frac {3}{9} \times \frac {4}{9} = \frac {4}{27}\)