Right choice is (a) x > log(x + 1)
The explanation is: Assume, f(x) = x – log(1 + x)
Therefore, f’(x) = 1 – (1/(1 + x))
= x/(x + 1) > 0, when x > 0
Hence, we must have, f(x) > f(0), when x > 0
But f(0) = 0 – log1 = 0
Thus, f(x) > 0, when x > 0 i.e.,
x – log(1 + x) > 0, when x > 0
Or x > (1 + x), when x > 0.