Right answer is (b) Twice
The best I can explain: If we consider the angular velocity of flow in plane of the airscrew blade as bΩ, and the angular velocity behind the blade as indicated by the bound vortices as +βΩ, then the angular velocity of the flow behind the airscrew is given by:
ω=(b+β)Ω=2bΩ
This value is twice that of the angular velocity in plane of the airscrew.