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Calculate the work done in a resistor of 20 ohm carrying 5A of current in 3 hours.

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in Basic Electrical Engineering by (88.7k points)
Calculate the work done in a resistor of 20 ohm carrying 5A of current in 3 hours.

(a) 1.5J

(b) 15J

(c) 1.5kWh

(d) 15kWh

I got this question in exam.

The above asked question is from Power in division Simple DC Networks of Basic Electrical Engineering

1 Answer

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Right choice is (c) 1.5kWh

Explanation: To find power: P=I^2R=5^2*20=500W=0.5kW.

To find Work done: W=Pt=0.5*3=1.5kWh.

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