Correct option is (b) equidistant
Explanation: In the figure below, for ∆’s AOM and CON
OM = ON (to prove)
OA = OC (radii of the same circle)
AM = CN OR 2AM = 2 CN (since OM ON are perpendicular to the chords and it bisects the chord and AM = MB, CN = ND)
Angle AMO and CNO = 90°
∆AOM similar to ∆CON (R.H.S rule)
OM = ON (CPCT) (required).