Question

Refer to Q12 and, calculate OTR. (Given: kLa = 169 mmol O2/ 1 hr atm, P* = 0.0263 atm and PO2 = 0.21 atm).

(a) 30.05 mmoles O2 / liter hr

(b) 31.05 mmoles O2 / liter hr

(c) 20.05 mmoles O2 / liter hr

(d) 21.05 mmoles O2 / liter hr

This question was addressed to me during an interview.

This interesting question is from Measurement of KLa in portion Mass Transfer of Bioprocess Engineering

Answer 1

Right choice is (b) 31.05 mmoles O2 / liter hr

To explain I would say: OTR = kLa(PO2 – P*)

= 169 mmol O2 / 1 hr atm(0.21- 0.0263) atm

= 31.05 mmoles O2 / liter hr.