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Diameter of wire is 7.5 mm and spring index is 15. Outer diameter of the coil is ___________

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Diameter of wire is 7.5 mm and spring index is 15. Outer diameter of the coil is ___________

(a) 112.5 mm

(b) 120 mm

(c) 1.2 cm

(d) 20 cm

The question was asked in final exam.

Origin of the question is Construction of Helical Springs topic in chapter Curves used in Engineering Practice of Engineering Drawing

1 Answer

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Correct answer is (b) 120 mm

Easy explanation: The ratio of mean diameter of coil to diameter of wire gives spring index. Mean diameter is average of outer and inner diameter of coil in other words outer diameter = diameter of wire +mean diameter or inner diameter = mean diameter – diameter of wire. Mean diameter = 7.5 x 15 = 112.5 mm. Outer diameter = 112.5 mm + 7.5 mm = 120 mm.

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