The correct option is (b) ^5!6!⁄11!
The explanation is: Using the definition of beta function we see that the integral is equal to the beta function at (6,5)
Now using the relation between the Beta and the Gamma function we have
\(\beta(m, n)=\frac{\Gamma (m).\Gamma (n)}{\Gamma (m+n)}\)
\(\beta(6, 5)=\frac{\Gamma (6).\Gamma (5)}{\Gamma (11)}=\frac{6!.5!}{11!}\)